For any bounded subset A of L^1 space, exists x fixed by every isometry of L^1 preserving A

You need to know: Banach space B with norm ||.||, linear map f:B\to B, bounded subset of B, L^1 space.

Background: Let B be a Banach space. A linear map f:B\to B is called an isometry if ||f(x)||=||x|| for all x \in B. For a subset A \subset B, we say that f preserves A if f(x) \in A for all x \in A. A point x\in B is called a fixed point of f if f(x)=x.

The Theorem: On 7th December 2010, Uri Bader, Tsachik Gelander, and Nicolas Monod submitted to arxiv and Inventiones Mathematicae a paper in which they proved the following result. Let A be a non-empty bounded subset of an L^1 space B. Then there is a point in B fixed by every isometry of B preserving A. Moreover, one can choose a fixed point which minimises \sup\limits_{a\in A}||v-a|| over all v \in B.

Short context: Starting with famous Banach’s Fixed Point Theorem, mathematicians developed fixed point theorems in various contexts, useful in different applications, see here for an example. The Theorem is a version of fixed point theorem for L1 spaces. The authors demonstrated that it has many applications. For example, it can be used to derive the optimal solution to so-called “derivation problem”, see the original paper for details.

Links: Free arxiv version of the original paper is here, journal version is here.

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